5x^2+x-3=44

Solution for 5x^2+x-3=44 equation:

5x^2+x-3=44

We move all terms to the left:

5x^2+x-3-(44)=0

We add all the numbers together, and all the variables

5x^2+x-47=0

a = 5; b = 1; c = -47;
Δ = b2-4ac
Δ = 12-4·5·(-47)
Δ = 941
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{941}}{2*5}=\frac{-1-\sqrt{941}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{941}}{2*5}=\frac{-1+\sqrt{941}}{10}
$